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1.

You are asked to find the boy’s lever arm.

2.

You are given the two masses and the cat’s lever arm.

3.

Use: = r F,  and  F = mg

4.

Solve  for the cat:  = (2 m)(4 kg)(9.8 N/kg) = +78.4 Nm

5.

Solve for the boy:  = (d )(50 kg)(9.8 N/kg) = -490 d

For rotational equilibrium, the net torque must be zero.

0= 78.4 – 490d  d = 0.16 m.  The boy must sit 16 cm from center.

Solve a rotational equilibrium problem

A boy and his cat sit on a seesaw. The cat has a mass of 4 kg and sits 2 m from the center of rotation.  If the boy has a mass of 50 kg, where should he sit so that the see-saw will balance?

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