# Gas Law Stoichiometry - I - NH_{3 }+ HCl

Problem: A slide separating two containers is removed, and the gases are allowed to mix and react. The first container with a volume of 2.79 L contains Ammonia gas at a pressure of 0.776 atm and temperature = 18.7 ^{o}C. The second with a volume of 1.16 L contains HCl gas at a pressure of 0.932 atm and a temperature of 18.7 ^{o}C. What mass of solid ammonium chloride will be formed, and what will be remaining in the container, and what is the pressure? Plan: This is a limiting reactant problem, so we must calculate the moles of each reactant using the gas law to determine the limiting reagent. Then we can calculate the mass of product, and determine what is left in the

combined volume of the container, and the conditions.

Solution: Equation:

NH_{3 (g) }

+

HCl

_{(g) }

NH_{3 }

NH_{4}Cl_{(s) }

HCl

# T_{NH3 }

= 18.7 ^{o}C + 273.15 = 291.9 K