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Applied Problems: Motion - page 33 / 38

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48

2nd leg

60

1st leg

Distance

Time

Rate

Bernadette drove 120 miles. The first part of the trip she averaged 60 mph, but on the second part of the trip she ran into some congestion and averaged 48 mph. If the total driving time was 2.2 hours, how much time did she spend at 60 mph?

What is the picture for this problem?

t

2.2 - t

60t

48(2.2 – t)

Do you see the equation from the picture?

Dist 1st leg             Dist 2nd leg

60t

48(2.2 – t)

Total dist. 120 miles

60t +48(2.2 – t) = 120

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