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Adding half-equations part 2

The alternative is to get equal numbers of electrons on each side

E.g. displacement of copper from one of its compounds by magnesium

½ equation :    Mg(s) – 2e- Mg2+(aq)

½ equation :    Cu(s) – 2e- Cu2+(aq)

+ (in this case) the reverse of : Mg(s) – 2e- + Cu2+(aq) Mg2+(aq) + Cu(s) – 2e-

Or         Mg(s) + Cu2+(aq) Mg2+(aq) + Cu(s)

Looks harder but that depends on what they give you in the question...

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